How to find the magnetic force on and acceleration

Topic:-Magnetic force on and Acceleration

A magnetic field is a vector field which surrounds magnets and electric currents, and is detected by the force it exerts on moving electric charges and on magnetic materials and acceleration is the change in velocity over time.

Let's see how these two works along with each other in the following problem.

Question:-

If we have an 8.2A current running through a 0.012meter wire, with a magnetic fields strength of 1.2T, what would be the direction of the force and what would be the acceleration of the 0.32kg wire? Find the net force, direction and acceleration?

ANSWER:

This physics help explanation is based direction of force.

Net force=0.11808N, Acceleration=.01296*10³¹ m/sec²

Here,

I=8.2A

Mass= 0.32kg

L =0.012meter

B=1.2T

F=BIl sinθ, here θ=90, so sinθ=1

Force on a current carrying wire of length l is=0.11808N

F is perpendicular to both E and B

Acceleration=F/m= .01296*10³¹ m/sec<sup>2



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Question on Displacement of a body at Uniform Motion

When a body moves from one place to another place then it is called displacement. Displacement can occur due to external force, may be balanced forces or unbalanced forces.

Body displaces either of the types of motion called uniform motion or non-uniform motion.

Topic : Average velocity of body under motion

Velocity of a body is a speed at which body displaces in a given time.

Question : A man traveled 100 m towards north at 10 m/s, then 200 m towards north at 25 m/s. What is the hiker's average velocity?

Solution :

Time taken travel 100 m north (t1) = displacement / velocity = 100m/10m/s = 10 s
Time taken travel 200 m north (t2) = displacement / velocity = 200m/25m/s = 8 s

Total Time taken (t) = t1 + t2 = 10 + 8 = 18 s

Total displacement = 200m + 100 m = 300 m

Average velocity = displacement / time
= 300m/ 18 s
= 16.67 m/s due north

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